Study Guide
Field 242: MultiSubject: Secondary Teachers
(Grade 7 to Grade 12)
Part Two: Mathematics
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Sample SelectedResponse Questions
The following reference material will be available to you during the test:
Competency 0001
Number and Quantity
1. Grapes are 80 percent water by weight and raisins are 15 percent water by weight. If 100 pounds of grapes are dried to make raisins, which weight is closest to the weight of the raisins?
 24 pounds
 32 pounds
 75 pounds
 85 pounds
 Enter to expand or collapse answer. Answer expanded
 Correct Response: A. This question requires the examinee to use proportional relationships to solve a multistep ratio and percent problem. If grapes are 80 percent water by weight, then 20 percent of the weight is not water, so 100 pounds of grapes contain 20 pounds of nonwater matter. These 20 pounds must make up the nonwater matter in the raisins. Since raisins are 15 percent water by weight, the nonwater matter is 85 percent of the weight, so 20 equals 0.85 (total weight) and total weight of the raisins is 20 divided by 0.85 or about 24 pounds.
Competency 0002
Algebra and Functions
2. Use the graph below to answer the question that follows.
Graph. Curved line starting high near the y axis and decreasing very quickly almost vertically then decreasing more slowly passing through the single point open parenthesis one comma two close parenthesis then slowing the decrease to an almost horizontal decrease.
The graph shows a function of the form y equals f left paren x right paren equals c over square root of x for constant c and x is greater than 0 What is the inverse function of y equals f left paren x right paren for x is greater than zero?
 y equals two times square root of x
 y = 2 x squared
 y equals four over x squared
 y equals negative four over square root of x
 Enter to expand or collapse answer. Answer expanded
 Correct Response: C. This question requires the examinee to build new functions from existing functions. Since the graph contains the point (1, 2), substituting 1 for x and 2 for y calculates c equals 2 Then y equals two over square root of x Inverse functions reverse the roles of x and y, so an equation for the inverse is x equals two over square root of y Squaring both sides, x squared equals four over y which yields x squared y equals 4 which yields y equals four over x squared
Competency 0003
Geometry and Statistics
3. Use the diagram below to answer the question that follows.
right cylinder with a rectangular cross section length wise inserted inside of it that is four feet up from the bottom.
The fuselage of an airplane is modeled as a right circular cylinder with a diameter of 20 feet and a length of 200 feet. A platform is built into the cylinder to serve as a floor for cargo, as shown in the crosssection diagram. How much floor space, in square feet, is provided if the platform is positioned 4 feet above the bottom of the fuselage?
 2400 feet squared
 3200 feet squared
 4800 feet squared
 9600 feet squared
 Enter to expand or collapse answer. Answer expanded

Correct Response: B. This question requires the examinee to analyze
the shape of a twodimensional cross section of a threedimensional object. The
floor in question is a rectangle of length 200 feet, whose width must be calculated.
Using the diagram below,
A B
is the width of the floor and also a chord
of the circular cross section whose diameter is 20 feet and radius is 10 feet. A
radius drawn perpendicular to a chord bisects it, so
left paren A D right paren squared plus 6 squared equals 10 squared
A D equals 8
and
A B equals 16
The area of the floor is
16 times 200 equals square feet
circle with center point p radii drawn from p to a on the bottom left side that is ten feet another radii drawn vertically from p to the bottom of the circle the the right of a there is a segment drawn horizontally from a on the left to b on the right of the circle point d is labeled where the line segment a b intersects the vertical radii from p to the outer circle segment p d is labeled six feet and the rest of that radi from d to the outer part of the circle is labeled four feet the points p d a make a right triangle with its hypotenuse being a p ten feet and the leg p d is six feet.